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There are numbers (pervyness) and (vtoroya) finally, some mathematical manipulation we get (tretinon) numbers. All these sets are famous, but the algorithm for obtaining the third. What could be the actions on the first sets of numbers (iteration algorithm) to brute force iterate and in the end to the third set?
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You can start to try to build a surface in the axes XYZ and appreciate the perspective on how difficult the addiction, maybe there is even a plane or a typical hyperboloid of rotation or the ball will. If the surface is recognizable it is likely that there are ready-made formulas describe the type remains the method of successive approximations to find the coefficients.
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If the surface is not recognizable then everything gets complicated at times, but then savvy can help and make everything easier.
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If the algorithm is not known, it does.
If given two the third is brute force, the number of options for brute force — the power of (number of options) the first set multiplied by the second power.
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As a pretty wild option is to build a neural network with two inputs and train with these sets.
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to find the algorithm for these sets is possible, but whether the same algorithm to work on other sets?
let's say you have that from A and B according to the algorithm "X" turns, you've picked up any algorithm Y which satisfy these conditions. But not the fact that for the other set A1, the algorithm B1 X and Y will give the same result
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Many options are endless. For example, imagine that the third set is a hash of the original data with the known algorithm, but with an unknown salt. So brute force does not work, no data needed.
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Describe the format of the incoming and outgoing data, show examples of known you the features of the algorithm and so on. Then maybe you can say something specific.
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