Java: How to pass an exception in the constructor of the singleton class getInstance()?

In this version — no way.
Solutions
1. Use the Spring to a singleton instance (best)
2. Perversion is in the designer make try{}catch{}(). If there is acceptn — save it in another static variable. getInstance() will check if saved acceptn — it will throw out if no — go to field with the instance and return it. Only I wouldn't do :)
3. Initialize the singleton at the beginning of the program. In one place. Then you don't have to write a getInstance() and use a public static field of a class
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Seriously — if the singleton's constructor can throw, acceptn — use Spring, Luke

What this code does not fit?
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public class ThrowSingleton { static public void main(String args[]) throws Throwable { SingletonClass.getInstance().toString(); } } class SingletonClass { public SingletonClass() throws Throwable { throw new Exception(); } private static SingletonClass instance; public static SingletonClass getInstance() throws Throwable { if (instance != null) { instance = new SingletonClass(); } return SingletonClass.instance; } } 

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I do not quite understand why make a private subclass which keeps a singleton.

The first two options here for you.